Saturday, August 15, 2009

Problem 337. Isosceles Trapezoid, Angle bisector, Parallel, Concyclic points

Proposed Problem
Click the figure below to see the complete problem 337 about Isosceles Trapezoid inscribed in a circle, Angle bisector, Parallel, Concyclic points.

Problem 337. Isosceles Trapezoid, Angle bisector, Parallel, Concyclic points.
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Complete Problem 337
Level: High School, SAT Prep, College geometry

Posted by Antonio Gutierrez at 8:50 AM
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1 comments:

  1. ang ADC + ang BCD = 180 (from ang of one side in trap)

    so need to prove ang EDH(C) + ang EGH = 180

    ang EDC = ang ADC + ADE (or ECD), (CE bisector)
    so for ang EDC have to add ECB ( BCD - ECD )
    but ECB = EBC ( equal bisector for equal ang )
    so ang EGH = ang EBC (are at the same side of L1 //BC)

    ReplyDelete

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