Online Geometry theorems, problems, solutions, and related topics.
Proposed ProblemClick the figure below to see the complete problem 306.See also:Complete Problem 306Collection of Geometry ProblemsLevel: High School, SAT Prep, College geometry
From triangle BCE, x^2 = b^2 + BC^2. Now triangles BCE & FAB are similar; hence, a/AB =BC/b or BC^2 = ab since AB=BC. Thus, x^2 = b^2 +ab. QED.