Proposed Problem

See complete Problem 26 at:

gogeometry.com/problem/p026_right_triangle_incircles_incenter.htm

Level: High School, SAT Prep, College geometry

## Thursday, April 9, 2009

### Problem 26: Right triangle, Altitude, Incircles, Inradius

Labels:
altitude,
incircle,
inradius,
right triangle

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From Problem 25, FG=BE but BE^= r^2 +r^2 = 2r^2 since E is the incentre of Tr. ABC with angle B=90. Thus, FG = BE = V2 r

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This follows easily from my proof for Problem 25

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