Proposed Problem

See complete Problem 273 at:

gogeometry.com/problem/p273_triangle_perpendicular_squares_areas.htm

Level: High School, SAT Prep, College geometry

## Sunday, March 22, 2009

### Problem 273: Triangle, Perpendiculars, Area of Squares

Labels:
area,
perpendicular,
square,
triangle

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S1 = AD^2 = OA^2 - OD^2

ReplyDeleteS3 = BE^2 = OB^2 - OE^2

S5 = CF^2 = OC^2 - OF^2

Or,S1+ S3 + S5= OA^2-OD^2+OB^2 -OE^2+OC^2-OF^2

=(OB^2-OD^2)+(OC^2-OE^2)+(OA^2-OF^2)

= BD^2 + CE^2 + AF^2

= S2 + S4 + S6

QED

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