Thursday, March 12, 2009

Problem 267: Right Triangle, Product of Catheti

Proposed Problem
Problem 267. Right Triangle, Product of Catheti.

See complete Problem 267 at:
gogeometry.com/problem/p267_right_triangle_catheti_product.htm

Level: High School, SAT Prep, College geometry

6 comments:

  1. Area of Tr. ABC = (1/2)*c*h
    Since BC is perpendicular to AC,area of Tr. ABC is also=(1/2)*b*c. Thus (1/2)*c*h = =(1/2)*b*c
    or a*b = c*h
    Ajit: ajitathle@gmail.com

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  2. Typo Correction
    The second line in my proof above should've read:
    Since BC is perpendicular to AC, area of Tr. ABC is also=(1/2)*a*b. Thus (1/2)*c*h = =(1/2)*a*b
    Ajit

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  3. Triangles ABC and ACH are similar therefore :

    a/c=h/b
    ab=ch

    ReplyDelete
  4. https://www.youtube.com/watch?v=PlUisGWx3nM

    ReplyDelete