Monday, December 22, 2008

Bottema's Theorem: Triangle and Squares

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Draw squares ABDE and BCFG on sides AB and BC of a triangle ABC. Then the midpoint M of EF is independent of B and the triangle AMC is an isosceles right triangle.

Bottema's Theorem: Triangle and Squares.
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1 comment:

  1. this's actually not hard to prove.
    T: midpoint of AC
    Let M,N,P be the points so that EM,FN, BP is perpendicular to AC.
    easily have: EM+FN=AC=2MT => MT // EM=> M is independant