Sunday, November 16, 2008

Elearn Geometry Problem 208: Triangle, Excircles, Angles, 360 degrees

Right triangle

See complete Problem 208 at:
gogeometry.com/problem/p208_triangle_excircles_angles.htm

Triangle, Excircles, Angles, 360 degrees. Level: High School, SAT Prep, College geometry.

2 comments:

  1. with the exteror angles of ABC ,and isoscele triangles like BEF we have:
    alpha = 180-(B/2+C/2)
    beta = 180-(C/2+A/2)
    gamma = 180-(A/2+B/2)
    sum = 3.180-180=360
    .-.

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  2. Let :

    ∠ABC=s
    ∠ACB=u
    ∠BAC=t

    Let O be the center of the circle E_a. Then join DO and OF.
    Extend DO to meet the circle at the point P

    ∠DPF=180-α

    therefore

    ∠DOF = 360-2α

    DOFC lies on a circle therefore

    (1.) 180+u=2α

    Working in the same way we can find similar formules for β and θ

    (2.)180+t=2β
    (3.)180+s=2θ


    Adding equations 1 ,2 and 3 with u+s+t=180

    2(α+β+θ)=540+s+t+u
    2(α+β+θ)=720
    α+β+θ=360

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