Proposition

Let A, B, C, D, E, F be points on a circle and makes a hexagon out of them in an arbitrary order. Then the three points L, M, N at which pairs of opposite sides meet, lie on a straight line. This line is called the Pascal line of the hexagon ABCDEF.

See complete interactive proof with animation and key concepts

Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

## Thursday, August 7, 2008

### Pascal's Mystic Hexagram Theorem Proof

Labels:
circle,
collinear,
hexagon,
Menelaus' theorem,
Pascal's theorem,
transversal,
triangle

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