See complete Problem 162 at:

www.gogeometry.com/problem/p162_parallelogram_triangle_area.htm

Parallelogram, Triangles, Areas. Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

## Sunday, August 24, 2008

### Elearn Geometry Problem 162

Labels:
area,
parallelogram,
similarity,
triangle

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From E draw a line parallel to AB (& DC) meeting FG in H. Now triangles FBM a& EMH are similar. Hence Tr FBM/Tr.EMH =BF^2/EH^2 = a^2/(ka)^2 or

ReplyDeleteS1 = Tr. EMH/k^2 Similarly S2 = Tr.ENH/k^2 Hence, S1+S2 = Tr. EMH/k^2 + Tr.ENH/k^2

= Tr. EMH/k^2

or S1 + S2 = Tr. EMH/k^2 = S/k^2. Hence etc.

Ajit: ajitathle@gmail.com