Sunday, August 17, 2008

Elearn Geometry Problem 161

Click to see complete problem

See complete Problem 161
Parallelogram, Midpoints, Octagon, Areas. Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

1 comment:

  1. The octagon have vertices, clockwise from top, M,N,O,P,Q,R,S,T, with center X. by rotational symmetry, F,M,X,Q,H ; E,S,X,O,G collinear. N is the centroid of XFG, XN cut FG at I. MI//XG & OI//XF, so [XMNO]=[NFG]; XM=MF & XO=OG, so [XMNO]=[NMF]+[NOG]; get [XMNO]/[XFG]=1/3. S1/S=[XMNO]/[XFCG]=1/2*[XMNO]/[XFG]=1/6