Proposition

Let ABC be a triangle and lines (or cevians) AD, BE, and CF joining vertices with opposite sides intersect at a single point P. Prove that: (AF.BD.CE)/(FB.DC.EA)=1. The converse is also true.

See complete interactive proof with animation and key concepts

Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

## Friday, August 1, 2008

### Ceva's Theorem Proof

Labels:
Ceva's theorem,
cevian,
concurrent,
Menelaus' theorem,
point,
triangle

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