See complete Problem 113

Area of Triangles, Incircle, Excircles. Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

## Tuesday, June 3, 2008

### Elearn Geometry Problem 113

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## Tuesday, June 3, 2008

###
Elearn Geometry Problem 113

Online Geometry theorems, problems, solutions, and related topics.

See complete Problem 113

Area of Triangles, Incircle, Excircles. Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

Subscribe to:
Post Comments (Atom)

MA=BF=p-c

ReplyDeleteDA=CG=p-b

CH=BE=p-a

all triangles have altitude r

S1=S1'=0.5r(p-b)

S2=S2'=0.5r(p-a)

S3=S3'=0.5r(p-c)

.-.

AD = CG = s - AC ...........(s = 1/2 perimeter)

ReplyDelete[IAD]= 1/2 . r . AD .......( r = inradius )

[ICG]= 1/2 . r . CG .......( r = inradius )

obviuos that [IAD] = [ICG]

With the same way , can be proved that :

[IBE]=[ICH]and [IBF]=[IAM]

Teddy A D (wteddyad@yahoo.com)