Monday, May 19, 2008

Geometry Problem 95

See complete Problem 95
Similar Triangles, Inradii, Parallel. Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

1 comment:

  1. Just saw the problem on the Mathematica Blog and followed the Mathematica Demo at
    So I wondered why it was true. Placing the radii of the incircles to the tangent points on BC and using similar triangles makes it clear:
    r/BC=r1/BE =r2/EG =r3/GC=(r1+r2+r3)/(BE+EG+GC).
    Since (BE+EG+GC=BC), r = r1+r2+r3.