Monday, May 19, 2008

Elearn Geometry Problem 64



See complete Problem 64
Triangle, Incircle, Transversal. Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

1 comment:

  1. By Menelaus's theorem, AG/GC*CE/EB*BD/DA = -1
    Remembering that CE=CF=e,DB=BE and FA=AD=d. we've (x+d+e)/x * e/EB *EB/d = 1. Hence,
    (x+d+e)/x * e/d = 1 or x = -e^2-ed/(e-d)
    = e(d+e)/(d-e)
    QED.
    Ajit: ajitathle@gmail.com

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