See complete Problem 56

Tangent Circles, Angle Bisector, Parallel. Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

## Monday, May 19, 2008

### Elearn Geometry Problem 56

Labels:
angle bisector,
circle,
parallel,
tangent

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ang CBG = ang QPG (1)( GQPB cyclic,arc GQ, see P 55 )

ReplyDeleteang CDG = ang CBG (2)( CDBG cyclic, arc CG )

from (1) & (2)

CDG = QPG

& as corresponding angles

=>

CD//PQ